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An aeroplane takes off at an angle of 60...

An aeroplane takes off at an angle of `60^(@)` to the horizontal. If the velocity of the plane is `200kmh^(-1)`,calculate its horizontal and vertical component of its velocity (in `kmh^(-1)`) .

A

`v_(x) =50` , `v_(y) = 10sqrt3`

B

`v_(x) =50sqrt3` , `v_(y) = 100sqrt3`

C

`v_(x) =100sqrt3` , `v_(y) = 100sqrt3`

D

`v_(x) =100` , `v_(y) = 100sqrt3`

Text Solution

Verified by Experts

The correct Answer is:
D
Here `v=200 km h^(-1),theta=60^(@)`

`:.`Horizontal component
`v_(x)=vcos theta=200cos60^(@)`
`=200xx1/2=100Km h^(-1)`
Vertical component
`v_(y)=vsin theta=200sin60^(@)=200xxsqrt(3)/2=100 sqrt3Km h^(-1)`
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