Two vector `vec(A)` and `vec(B)` have magnitudes A=3.00 and B=3.00. Their vector product is `vec(A)xxvec(B)=-5.00hat(k)+2.00hat(i)`.
What is the angle between `vec(A)` and `vec(B)`?

Answer

`sin^(-1)[sqrt(29)/9]`

Explanation

`|vec(A)xxvec(B)|=sqrt(5^(2)+2^(2))=sqrt(29)`
`sin theta=(|vec(A)xxvec(B)|)/(AB)=sqrt(29)/(3xx3) rArr theta=sin^(-1)[sqrt(29)/9]`