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A particle is projected vertically upwar...

A particle is projected vertically upwards. Prove that it will be at three-fourth of its greatest height at times which are in the ratio `1: 3`.

Text Solution

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`H=(u^(2))/(2g), u(1)/(2) g (t_(1)+t_(2)), h=(1)/(2)g t_(1)t_(2)`
Given `(t_(1))/(t_(2))=(1)/(2)`, solving we get `h=(3)/(4) H`
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