A moving sidewalk in an airport terminal building moves at a speed of `1.0 m s^(-1)` and is `35.0 m` relative to the moving sidewalk, then find the time that she requires to reach the opposite end `a` when she walks in the same direction the sidewalk is moving and `b` when she walks in the opposite derection.

Explanation

a. When she walks in the same direction, relative velocity of woman w.r.t. fround:
`v_(1)=1+1.5 =2.5 ms^(-1)`,
Time taken`=(s)/(v_(1)) =(35)/(2.5) =14 s`
b. When be she walks in the opposite derection, relative velcity of woman w.r.t. groun:
`v_(2)=1.5-12 =0.5 ms^(-1)`.
Time taken `=(s)/(v_(2))=(35)/(0.5) =70 s`.