Divede a plane `10 m` long and `5 m` high into three parts so that a body starting from rest takes equal times to slide down these. Also find the time taken then.

Answer

`(10)/(9) m`; `(30)/(9)m`; `(50)/(9)m`; `(2)/(3) s`

Explanation

`a=g sin theta =10 xx (5)/(10) =5 ms^(-2)`
`x_(1)=(1)/(2)at^(2), x_(1)+x_(2)=(1)/(2) a(2t)^(2)`
`10 =x_(1)+x_(2)+x_(3) =(1)/(2) a(3t)^(2)`
Solve to get `x_(1) =(10)/(9) m, x_(2) =(30)/(9) m, x_(30 =(50)/(9) m, `t=(2)/(3)s`.
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