A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in `T/3` second?

Options

A. ` h//9 m`
B. ` 7h//9 m`
C. ` 8h//9m`
D. ` 17 h//18 m`

Answer

C

Explanation

We have `h=(1)/(2)g T^(2)`
In `T//3` second, distance fallen `=(1)/(2) g((T)/(3))^(2) =(h)/(9)`
So position of the ball from the ground is `h-(h)/(9)=(8h)/(9)m`.