When the speed of a car is `u`, the mimimum distance over which it canbe stopped is `a`, If speed becomes `nu`, what will be the mimimum distance over which it can be stopped during the same time?

Options

A. ` s//h`
B. ` ns`
C. ` s//n^(2)`
D. `n^(2) s`

Answer

D

Explanation

`v^(2)-u^(2)=2as` , `v=0`
`prop u^(2)`,
When the initial velocity is made `n` times, the distance over which it can be stopped becomes `n^(2)` times.