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The dispacement of a body is given by 4s...

The dispacement of a body is given by `4s=M +2Nt^(4)`, where `M` and `N` are constants.
The velocity of the body at any instant is .

A

`(M+2Nt^(4))/(4)`

B

`2N`

C

` (M+2N)/(4)`

D

`2Nt^(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`s=(M+2Nt^(4))/(4) rArr v=(ds)/(dt) =2Nt^(3)`
Putting `1 s`, we get `v=2 N` .
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Knowledge Check

  • The dispacement of a body is given by 4s=M +2Nt^(4) , where M and N are constants. The velocity of the body at the end of 1 s from the start is .

    A
    `2N`
    B
    `(M+2N)/(4)`
    C
    `2(M_N)`
    D
    `(2M+N)/(4)`

  • The displacement of a body is given by 2 s= g t^(2) where g is a constant. The velocity of the body at any time t is :

    A
    `g t`
    B
    `g t//2`
    C
    `g t^(2)//2`
    D
    `g t^(3)//6`

  • The displacement of a body is given by s=(1)/(2)g t^(2) where g is acceleration due to gravity. The velocity of the body at any time t is

    A
    `(g t^(3))/(6)`
    B
    `(g t^(2))/(2)`
    C
    gt
    D
    `(g t)/(2)`
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