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The dispacement of a body is given by 4s...

The dispacement of a body is given by `4s=M +2Nt^(4)`, where `M` and `N` are constants.
The velocity of the body at any instant is .

A

`(M+2Nt^(4))/(4)`

B

`2N`

C

` (M+2N)/(4)`

D

`2Nt^(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`s=(M+2Nt^(4))/(4) rArr v=(ds)/(dt) =2Nt^(3)`
Putting `1 s`, we get `v=2 N` .
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Knowledge Check

  • The dispacement of a body is given by 4s=M +2Nt^(4) , where M and N are constants. The velocity of the body at the end of 1 s from the start is .

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