A body is moving with uniform velocity of `8 ms^-1`. When the body just crossed another body, the second one starts and moves with uniform acceleration of `4 ms^-2`. The time after which two bodies meet will be :

Options

A. `2s`
B. `4 s`
C. `6 s`
D. `8 s`

Answer

B

Explanation

b. Let they meet after time `t`, then the diatance travelled by both in time `t` should be same
`s=8t=(1)/(2) 4t^(2) rArr t =4 s`.