A body is allowed to fall from a height of `10 m`. If the time taken for the first `50 m` is `t_(1)` and for the remaining `50 s`,is `t_(2)`.
Which is correct?

Options

A. `t_(1)=t_(2)`
B. `t_(1) le t_(2)`
C. `t_(1) lt t_(2)`
D. `t_(1).t_(2)`

Answer

B

Explanation

`s=(1)/(2) g t_(1)^(2)` or `t_(1)^(2) =(50 xx 2)/(g) =(100)/(g)` or `t_(1) =(10)/(sqrtg)`
and `100 =(1)/(2) g t^(2)` or `t =(10 sqrt2)/(sqrtg)`
`t_(2) =t-t_(1) =(10)/(sqrtg) (sqrt2-1) =0. 4t_(1) t_(1)g t t_(2)`.