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A body is allowed to fall from a height of `10 m`. If the time taken for the first `50 m` is `t_(1)` and for the remaining `50 s`,is `t_(2)`.
The ratio of time to reach the ground and to reach first half of the distance is .

A

`sqrt3: 1`

B

`sqrt 2:1`

C

`5:2`

D

`1: sqrt3`

Text Solution

Verified by Experts

The correct Answer is:
B
`t`: `t_(1) =(10sqrt2)/(sqrtg) xx (sqrt g)/(10) =sqrt 2`.
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