A body is dropped from a balloon moving up with a velocity of `4 m s^(-2) ` when the balloon is at a height of `12.5 m` from the ground.
The height of the body after `5 s` from the ground is `(g=9.8 ms^(-2))`.

Options

A. `8 m`
B. `12 m`
C. `18 m`
D. `24 m`

Answer

C

Explanation

`s=ut+(1)/(2)at^(2)=4xx5-(1)/(2)xx9.8xx5^(2)=20-122.5=-102.5 m`
This shows that body is `102.5 m` below the initial position, i.e. height of the body `=120.5 -1002.5 =18 m` .