A ship is sailing due north at a speed of `1.25 ms^-1`. The current is taking it towards east at the rate of `2 ms^-1`. and a sailor is climbing a vertical pole in the ship at the rate of `0.25 ms^-1`. Find the magnitude of the velocity of the sailor with respect to ground.

Answer

`(3)/(2) sqrt((5)/(2)) m s^-1`

Explanation

`vec v_s = 2 hat i+ .25 hat j + 0.25 hat k`
Magnitude : `|vec v_s| = sqrt(2^2 + 1.25^2 + 0.25^2)`
=`(3)/(2) sqrt((5)/(2)) ms^-1`.