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From the top of tower of height 80 m, tw...

From the top of tower of height `80 m`, two stones are projected horizontally with velocities `20 m s^-1` and `30 m s^-1` in opposite directions, Find the distance between both the stones on reaching the ground `("in" 10^2 m)`.

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The correct Answer is:
2

`80 = (1)/(2) xx 10`
`t^2 = (80)/(5) rArr t = 4`
`x_1 = 20 xx 4 = 80`
`x_2 = 30 xx 4 = 120`
Separation `x_1 + x_2 = 80 +120 = 200 m`.
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