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A boy standing on a long railroad car th...

A boy standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of `1m/s^2` and the projectioon velocity into vertical direction is 9.8 m/s. How far behind the boy will the ball fall on the car?

Text Solution

Verified by Experts

The correct Answer is:
`(2)`
Let the velocity of car be `u` when the ball is thrown.
Initial velocity of car = Horizontal
velocity of ball.
Distance travelled by ball `B`,
`S_b = ut` (in horizontal direction)
Car has travelled extra distance
=`S_c = S_b = (1)/(2) at^2`
Ball can be considered a projectile having `theta = 90^@`
`t = (2 u sin theta)/(g)`
=`(2 xx 9.8)/(9.8) = 2 s`
`S_c - S_b = (1)/(2) at^2 = (1)/(2) (1) 2^2 = 2 m`
Hence, the ball will drop `2 m` behind the boy.
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