Home
Class 11
PHYSICS
A conservative force held function is gi...

A conservative force held function is given by `F=k//r^2`, where k is a constant.
a. Determine the potential energy funciton `U(r)` assuming zero potential energy at `r=r_0`.
b. Also, determine the potential energy at `r=oo`.

Text Solution

Verified by Experts

a. Using the definition of potential energy function,
`U(r)-U(r_0)=-int_(r_0)^rFdr`
`U(r)-U(r_0)=-kint_(r_0)^r(dr)/(r^2)=k[1/r]_(r_0)^r=k[1/r-1/r_0]`
Since at `r=r_0`, `U(r_0)=0`, therefore, `U(r)=k/r-k/r_0`
b. Potential energy at `r=oo` is `U_(oo)=-k//r_0`
Promotional Banner

Topper's Solved these Questions

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Solved Examples|15 Videos
  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Exercise 8.1|25 Videos
  • VECTORS

    CENGAGE PHYSICS|Exercise Exercise Multiple Correct|5 Videos

Similar Questions

Explore conceptually related problems

A conservative force in a region is given by vec F=(A/x^3)hati .An expression for the potential energy in the region, assuming the potential at infinity to be zero, is

In a conservative force field we can find the radial component of force from the potential energy function by using F = -(dU)/(dr) . Here, a positive force means repulsion and a negative force means attraction. From the given potential energy function U(r ) we can find the equilibrium position where force is zero. We can also find the ionisation energy which is the work done to move the particle from a certain position to infinity. Let us consider a case in which a particle is bound to a certain point at a distance r from the centre of the force. The potential energy of the particle is : U(r )=(A)/(r^(2))-(B)/(r ) where r is the distance from the centre of the force and A andB are positive constants. Answer the following questions. If the total energy of the particle is E=-(3B^(2))/(16A) , and it is known that the motion is radial only then the velocity is zero at

Assertion : On decreasing the distance between two masses potential energy increases. Reason : Potential energy U =(GMm)/(r) .

In a conservative force field we can find the radial component of force from the potential energy function by using F = -(dU)/(dr) . Here, a positive force means repulsion and a negative force means attraction. From the given potential energy function U(r ) we can find the equilibrium position where force is zero. We can also find the ionisation energy which is the work done to move the particle from a certain position to infinity. Let us consider a case in which a particle is bound to a certain point at a distance r from the centre of the force. The potential energy of the particle is : U(r )=(A)/(r^(2))-(B)/(r ) where r is the distance from the centre of the force and A andB are positive constants. Answer the following questions. The equilibrium distance is given by

In a conservative force field we can find the radial component of force from the potential energy function by using F = -(dU)/(dr) . Here, a positive force means repulsion and a negative force means attraction. From the given potential energy function U(r ) we can find the equilibrium position where force is zero. We can also find the ionisation energy which is the work done to move the particle from a certain position to infinity. Let us consider a case in which a particle is bound to a certain point at a distance r from the centre of the force. The potential energy of the particle is : U(r )=(A)/(r^(2))-(B)/(r ) where r is the distance from the centre of the force and A andB are positive constants. Answer the following questions. The equilibrium is

In a conservative force field we can find the radial component of force from the potential energy function by using F = -(dU)/(dr) . Here, a positive force means repulsion and a negative force means attraction. From the given potential energy function U(r ) we can find the equilibrium position where force is zero. We can also find the ionisation energy which is the work done to move the particle from a certain position to infinity. Let us consider a case in which a particle is bound to a certain point at a distance r from the centre of the force. The potential energy of the particle is : U(r )=(A)/(r^(2))-(B)/(r ) where r is the distance from the centre of the force and A andB are positive constants. Answer the following questions. The work required to move the particle from equilibrium distance to infinity is

In a certain region of space, the gravitational field is given by -k//r , where r is the distance and k is a constant. If the gravitational potential for the gravitational potential V ?

The potential energy for a conservative force system is given by U=ax^(2)-bx . Where a and b are constants find out (a) The expression of force (b) Potential energy at equilibrium.

A body is moving on a circlar path of radius r with constant speed under the action of force (K)/(r^(3)) Assuming infinity as zero potential energy reference, tick the correct alternative