Home
Class 11
PHYSICS
The potential energy of configuration ch...

The potential energy of configuration changes in x and y directions as `U=kxy`, where k is a positive constant. Find the force acting on the particle of the system as the function of x and y.

Text Solution

Verified by Experts

Substituting `U=kxy` in the expression
`F=-(delU)/(delx)hati-(delU)/(dely)hatj-(delU)/(delz)hatk`
we have `oversetrarrF=-k(yhati+xhatj)`
Promotional Banner

Topper's Solved these Questions

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Solved Examples|15 Videos
  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Exercise 8.1|25 Videos
  • VECTORS

    CENGAGE PHYSICS|Exercise Exercise Multiple Correct|5 Videos

Similar Questions

Explore conceptually related problems

The potential energy U for a force field vec (F) is such that U=- kxy where K is a constant . Then

The potential energy function of a particle in a region of space is given as U=(2xy+yz) J Here x,y and z are in metre. Find the force acting on the particle at a general point P(x,y,z).

If x and y are inversely proportional then _____ = k where k is positive constant.

If the potential energy function of a particle is given by U=-(x^2+y^2+z^2) J, whre x,y and z are in meters. Find the force acting on the particle at point A(1m,3m,5m) .

The potential energy of a particle with displacement X is U(X) . The motion is simple harmonic, when (K is a positive constant)

The potential energy function of a particle in the x-y plane is given by U =k(x+y) , where (k) is a constant. The work done by the conservative force in moving a particlae from (1,1) to (2,3) is .

The potential energy of a particle is determined by the expression U=alpha(x^2+y^2) , where alpha is a positive constant. The particle begins to move from a point with coordinates (3, 3) , only under the action of potential field force. Then its kinetic energy T at the instant when the particle is at a point with the coordinates (1,1) is

The potential energy of a particle of mass m is given by U(x)=U_0(1-cos cx) where U_0 and c are constants. Find the time period of small oscillations of the particle.