A `10-kg` block moves in a straight line under the action of a force that varies with position as shown in figure. How much work does the force do as the block moves from origin to `x=8m`?

Explanation

The area under the curve with respect to x-axis gives the total work done by the force as the block moves from `x=0` to `x=8m`.
Area=Work done
`=20+1/2(2)(10)+0-1/2(5)(2)=25J`