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Figure, a block slides along a track fro...

Figure, a block slides along a track from one level to a higher level by moving through an intermediate valley. The track is friction less until the block reaches the higher
level. Then there is friction force which stops the block at a distance d. The block's initial speed `v_0` is `6.0ms^-1`, the height difference `h` is `1.1m`, and the coefficient of kinetic friction `mu` is `0.60`. Find `d`.

Text Solution

Verified by Experts

Loss in kinetic energy=Gain in potential energy+Work done against friction
or `1/2mv_0^2=mgh+F_1xxd=mgh+mumgxxd`
Substituting `h=1.1m` and `mu=0.60`, we get
`d=1.2m`
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