Home
Class 11
PHYSICS
An elevator can carry a maximum load of ...

An elevator can carry a maximum load of `1800 kg` (elevator + passengers) is moving up with a constant speed of `2 ms^(-1)`. The friction force opposite the motion is `4000 N`.What is minimum power delivered by the motor to the elevator?

Text Solution

Verified by Experts

Weight of (elevator + passenger) `=mg=1800xx10N=18000N`
Frictional force `=4000N`
Total downward force on the elevator is
`(18000+4000)N=22000N`
Clearly, the motor must have enough power to balance this force.
Now power, `P=Fv=22,000Nxx2ms^-1=44,000W`
`=44000/746hp=58.98hp`
Promotional Banner

Topper's Solved these Questions

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Subjective|23 Videos

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Single Correct|100 Videos

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Exercise 8.4|16 Videos

  • VECTORS

    CENGAGE PHYSICS|Exercise Exercise Multiple Correct|5 Videos

Similar Questions

Explore conceptually related problems

An elevator can carry a maximum load of 1800 kg (celevator + passengers) is moving up with a constant speed of 2 ms^(-1) . The friction force oppposite the motion is 4000 N .What is minimum power delivered by the motor to the elevator?

An elevator that can carry a maximum load of 1500 kg (elvator+ passengers) is moving up with a constant speed of 2 ms^(-1). The frictional force opposing the motion is 3000 N. Find the minmum power delvered by the motor to the elevator in watts as well as in horse power (g=10ms^(-2))

An elevator which can carry a maximum load of 1800kg is moving with a constant speed of 2ms^(-1) . The frictional force opposing the motino is 5000N . Calculate the minimum power delivered by the motor to the elevator in watt and hp ? Take g=10m//s^(2)

Sand drops from a stationary hopper at the rate of 5kg//s on to a conveyor belt moving with a constant speed of 2m//s . What is the force required to keep the belt moving and what is the power delivered by the motor, moving the belt?

An object of mass 10kg moves at a constant speed of 10 ms^(-1) . A constant force, that acts for 4 sec on the object, gives it a speed of 2ms^(-1) in opposite direction. The force acting on the object is :

A truck of mass 500kg is moving with constant speed 10ms^(-1) . If sand is dropped into the truck at the constant rate 10kg/min ,the force required to mainatain the motion with constant velocity is .