A bus can be stopped by applying a retarding force F when it is moving with speed v on a level road. The distance covered by it before coming to rest is `s`. If the load of the bus increase by 50% because of passengers, for the same speed and same retarding force, the distance covered by the bus to come to rest shall be

Options

A. `1.5s`
B. `2s`
C. `1s`
D. `2.5s`

Answer

A

Explanation

First case: `1/2mv^2=Fs`
`1/2(M+m/2)v^2=Fs^'`
Dividing Eq. (ii) by Eq. (i), we get `(s^')/(s)=3/2` or `s^'=1.5s`