Power supplied to a mass `2 kg` varies with time as `P = (3t^(2))/(2)` watt. Here `t` is in second . If velocity of particle at `t = 0` is `v = 0`, the velocity of particle at time `t = 2s` will be:

Options

A. (a) `1ms^-1`
B. (b) `4ms^-1`
C. (c) `2ms^-1`
D. (d) `2sqrt2ms^-1`

Answer

C

Explanation

From work-energy theorem,
`DeltaKE=W_(n et)` or `K_f-K_i=int Pdt`
or `1/2mv^2-0=underset0overset2int(3/2t^2)dt`
or `v^2=|t^3/2|_0^2` or `v=2ms^-1`