A single conservative force `F(x)` acts on a `1.0-kg` particle that moves along the x-axis. The potential energy `U(x)` is given by `U(x)=20+(x-2)^2` where x is in meters. At `x=5.0m`, the particle has a kinetic energy of `20J`.
The maximum kinetic energy of the particle and the value of x at which maximum kinetic energy occurs are

Options

A. (a) `29J,0m`
B. (b) `49J,0m`
C. (c) `49J,2m`
D. (d) `29J,2m`

Answer

D

Explanation

KE is maximum, where U is minimum and
`U_(min)=20J` at `x=2m`,
`K_(max)=E-U_(min)=49-20=29J`