Home
Class 11
PHYSICS
In figuer, shown all the surfaces are fr...

In figuer, shown all the surfaces are frictionless, and mass of the block is `m=100g`. The block and the wedge are held initially at rest. Now the wedge is given a horizontal acceleration of `10ms^-2` by applying a force on the wedge, so that the block does not slip on the wedge. Then find the work done in joules by the normal force in ground frame on the block in `1s`.

A

5J

B

2J

C

10J

D

15J

Text Solution

Verified by Experts

The correct Answer is:
A
If block does not slip then, `a=g tan theta`
`implies 10=10 tan thetaimplies theta=45^@`

`N sin theta=maimpliesNxx1/sqrt2=0.1xx10impliesN=sqrt2N`
`S=1/2xxat^2=1/2xx10(1)^2=5m`
`W_N=NS cos theta=sqrt2xx5xx1//sqrt2=5J`
Alternatively: `W_N=1/2mv^2=1/2(0.1)(at)^2=5J`
Promotional Banner

Topper's Solved these Questions

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Archives (sinble Correct )|19 Videos

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Archives(multiple Correct)|3 Videos

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS|Exercise Linked Comprehension|55 Videos

  • VECTORS

    CENGAGE PHYSICS|Exercise Exercise Multiple Correct|5 Videos

Similar Questions

Explore conceptually related problems

In the figure shown all the surfaces are frictionless, and mass of the block 'm' is 1 kg. The block and wedge are held initially at rest. Now wedge is given a horizontal acceleration of 5 m/s^(2) by applying a force on the wedge, so that the block does not slip on the wedge. Then work done by the normal force in ground frame on the block in 2 sec is : (##NAR_NEET_PHY_XI_P2_C06_E09_012_Q01.png" width="80%">

In the figure shown all the surfaces are frictionless and mass of block m=1kg , block and wedge are held initially at rest, now wedge is given a horizontal acceleration of 10 m//s^(2) by applying a force on the wedge so that the block does not slip on the wedge, the work done by normal force in ground frame on the block in sqrt(3) sec is .

A block of mass 1.0 kg rests on a wedge of angle theta . The acceleration which should be given to the wedge so that the block falls freely is :

What force should be applied on the wedge so that block over it does not move? (All surfaces are smooth)

A block of mass m is placed on a smooth wedge of wedge angle theta The whole system is accelerated horizontally so that the block does not slip on the wedge. The force (normal reaction) exerted by the wedge on the block has a magnitude:

A block of mass m is placed on a smooth wedge of inclination theta . The whole system is accelerated horizontally, so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

As shown in the figure a block of mass 'm' is placed on a smooth wedge moving with constant acceleration such that block does not move with respect to the wedge. Find work done by the net force on the block in time t. (Initial speed is 0)

A block of mass m is placed on a smooth wedge of incination theta . The whole system s acelerated horizontally so tht the block does not slip on the wedge. The force exerted by the wedge on the block has a magnitude

A block of mass m is placed on a smooth wedge of inclination theta & mass M. The whole system is slip on the wedge. Then the normal reaction on the wedge acting from the ground :

A wedge with mass M rests on a frictionless horizontal surface A block with mass m is placed on the wedge. There is no friction between the block and the wedge. A horizontal force f is applied to the wedge. What magnitude F must have if the block is to remain at constant height above the table top?