A bullet of mass 0.1 kg is fired with a speed of `100 ms^(-1)`. The mass of gun being 50 kg. Then, the velocity of recoil becomes

Options

A. `0.05 ms^(-1)`
B. `0.5 ms^(-1)`
C. `0.1 ms^(-1)`
D. `0.2 ms^(-1)`

Answer

D

Explanation

From the law of conservation of momentum,
Total initial momentum = Total final momentum
`implies m_(1)u_(1)+m_(2)u_(2)=m_(1)v_(1)+m_(2)v_(2)`
`:. 0.1 xx0+50 xx0=0.1xx100+50(-v_(2))`
`implies 0=10-50 v_(2)`
`:. v_(2)=10/50 =0.2 ms^(-1)`