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A body of mass m moving with velocity v collides head on with another body of mass 2 m which is initially at rest. The ratio of K.E. of colliding body before and after collision will be

A

`1 : 1`

B

`2 : 1`

C

`4 : 1`

D

`9 : 1`

Text Solution

Verified by Experts

The correct Answer is:
D
`v_(2)'=((m_(2)-m_(1))/(m_(2)+m_(1)))v_(2)+((2m_(1))/(m_(1)+m_(2)))v_(1)`
`v_(1)=0`
`:. v_(2)/(v_(2)')=((m_(2)+m_(1))/(m_(2)-3`
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