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Moment of a force of megnitude 20 N acti...

Moment of a force of megnitude 20 N acting along positive x direction at point (3m 0, 0) about the point (0, 2, 0) (in N-m) is :-

A

20

B

60

C

40

D

30

Text Solution

Verified by Experts

The correct Answer is:
C
Torque, `tau=r xx F`
`=[(0-3) hat(i)+(2-0) hat(j)+(0-0) hat(k)]xx[20 hat(i)]`
`=[-3 hat(i)+2hat(j)]xx[20 hat(i)]=-40 hat(k)`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-FORCE-Exercise 1
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