At a depth of 1000 m in an ocean (a) what is the absolute pressure? (b) what is the gauge pressure? (c ) Find the force acting on the window of area `20 cm xx 20cm` of a submarine at this depth, the interior of which is maintained at sea-level atmospheric pressure. The density of sea water is `1.03 xx 10^(3) kg m^(-3)`, `g=10ms^(-2)`. Atmospheric pressure = `1.01 xx 10^(5) Pa`.

Options

A. 40 atm
B. 52 atm
C. 32 atm
D. 62 atm

Answer

B

Explanation

Absolute pressure `p=p_a+rhogh`
here `p_a=1.01xx10^5Pa`
`p=1.03xx10^3kgm^(-3)`
`therefore " " p=1.01xx10^5Pa + 51.5 xx 10^5 Pa`
`=1.01xx10^5 Pa + 51.5xx10^5 Pa`
`=52.5xx10^5 pa = 52` atm