A horizontal pipeline carries water in a streamline flow. At a point along the pipe, where the cross- sectional area is `10cm^2`, the water velocity is `1ms^-1` and the pressure is 2000 Pa. The pressure of water at another point where the cross-sectional area is `5cm^2`, is........Pa. (Density of water `=10^3kg.m^-3`)

Options

A. 4000 Pa
B. 2000 Pa
C. 1000 Pa
D. 500 pa

Answer

D

Explanation

According to equation of continuity
`A_1v_1=A_2v_2`
`10xx1=5xxv_2 rArr v_2=2ms^(-1)`
Now applying bernoull's equation we get
`therefore p_1/rho + v_1^2/2=p_2/rho + v_2^2/2`
`rArr 2000/1000 + 1^2/2 = (p_2)/(1000) + (2^2)/(2)`
`rArr p_2 = 5000 Pa`