Water flows along horizontal pipe whose cross-section is not constant. The pressureis 1 cam of Hg, where the veloecity is 35 cm/s . At a point where the velocity is 65cm/s then pressure will be

Options

A. 0.89 cm of Hg
B. 0.62 cm of Hg
C. 0.5 cm of Hg
D. 1cm of Hg

Answer

A

Explanation

Applying bernoulli's equation , we get
`p_1+1/2 rho v_1^2 = p_2+1/2rhov_2^2`
or `(10^(-2) cc 13.6 xx 10^3 xx10)+1/2 xx10^3xx(0.35)^2`
`=p_2+1/2xx10^3xx(0.65)^2`
or `p_2=1210Nm^(-2) = (1210xx10^2)/(13.6xx10^3xx10)` cm of Hg
=0.89 cm of Hg