Figure shows how the stream of water emerging from a faucet necks donw as it falls. The area changes from `A_(0)` to A through a fall of h. At what rate does the water flow from the tap ?

Options

A. `A_0sqrt((2ghA^2)/(A_0^2-A^2))`
B. `2A_0sqrt((ghA^2)/(A_0^2-A^2))`
C. `A_0sqrt((gh)/(2))`
D. `2Asqrt((ghA_0^2)/(A_0^2-A^2))`

Answer

A

Explanation

As , `A_0v_0 = Av rArr v^2 =v_0^2 + 2gh`
`rArr v_0=sqrt((2ghA^2)/(A_0^2 - A^2))`
or `R=A_0v_0=A_0sqrt((2ghA^2)/(A_0^2-A^2))`