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An arc of a circle of raduis R subtends ...

An arc of a circle of raduis `R` subtends an angle `(pi)/2` at the centre. It carriers a current `i`. The magnetic field at the centre will be

A

`(mu_(0)i)/(2R)`

B

`(mu_(0)i)/(8R)`

C

`(mu_(0)i)/(4R)`

D

`(2mu_(0)i)/(5R)`

Text Solution

Verified by Experts

The correct Answer is:
B
Magnetic field at the centre of arc is given by
`B=(mu_(0))/( 4pi)(theta i)/(r)=(mu_(0))/(4p)xx(pi)/(2)xx(i)/(R)=(mu_(0)i)/(8R)`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-MAGNETIC EFFECT OF ELECTRIC CURRENT -I-EXERCISE -1 TOPICAL PROBLEMS)
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  3. An arc of a circle of raduis R subtends an angle (pi)/2 at the centre....

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  10. A strong magnetic field is applied on a stationary electron, then

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  13. A conducting loop carrying a current i is placed in a uniform magnetic...

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  15. Two parallel conductors A and B of equal lengths carry currents I and ...

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  16. Two thin, long, parallel wires, separated by a distance 'd' carry a cu...

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  17. Two long conductors, separated by a distance d carry current I(1) and ...

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  18. Currents of 10A, 2A are passed through two parallel wires A and B resp...

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