A particle carrying a charge equal to `100` times the charge on an electron is rotating per second in a circular path of radius `0.8 metre`. The value of the magnetic field produced at the centre will be (`mu_(0)=` permeability for vacuum)

Options

A. `(10^(-7))/(mu_(0))`
B. `10^(-7)mu_(0)`
C. `10^(-6)mu_(0)`
D. `10^(-7)mu_(0)`

Answer

B

Explanation

Current produced in wire. `i=(q)/(t)=(100xxe)/(1)`
`:. i=100e`
Magnetic field at the centre of circular path
`=(mu_(0))/(4pi)*(2pi)/(r)=(mu_(0))/(4pi)*(2pixx100e)/(r)`
`=(mu_(0))200xx16xx10^(-19))/(2xx0.8)=10^(-17)mu_(0)`