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Two long conductors, separated by a dist...

Two long conductors, separated by a distance `d` carry current `I_(1) and I_(2)` in the same direction . They exert a force `F` on each other. Now the current in one of them is increased to two times and its direction is reversed . The distance is also increased to `3d`. The new value of the force between them is

A

`-(F)/(3)`

B

`(F)/(3)`

C

`(2F)/(3)`

D

`(-2F)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
D

Force between two conductors,
`F prop=(i_(1)i_(2))/(d)`
When `l_(2)` is changed to `2 l_(1)` and d is changed to 3d.
`:. F prop=((2i_(1))(i_(2)))/(3d)prop(2)/(3)F`
As direction of current is reversed so,
`F'=-2F//3`
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