Due to a small magnet intensity at a distance `x` in the end on position is `9` Gauss. What will be the intensity at a distance `(x)/(2)` on broad side on position?

Options

A. 9 gauss
B. 4 gauss
C. 36 gauss
D. 4.5 gauss

Answer

C

Explanation

In CGS`,B_("axial")=9=(2M)/(x^(3))` ...........(i)
` B_("equatorial")=(M)/(((x)/(2))^(2))=(8M)/(x^(3))` ........(ii)
From Eq. (i) and (ii) , `B_("equatorial")=36`gauss