The dip at a place is delta. For measuring it, the axis of the dip needle is perpendicular to the magnetic meridian. If the axis of the dip needle makes angle `theta` with the magnetic meridian, the apparent dip will be given `tan delta_(1)` which is equal to:

Options

A. `tan delta "cosec" theta `
B. `tan delta sin theta `
C. `tan delta cos theta `
D. `tan delta sec theta `

Answer

A

Explanation

As , ` tan delta=(V)/(H) and tan delta_(1)=(V)/(H cos (90^(@) - theta ))`
`= ( tan delta)/( cos (90^(@)- theta ))= tan delta "cosec" theta `