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A dip circle is at right angles to the m...

A dip circle is at right angles to the magnetic meridian. What will be the apparent dip ?

A

`0^(@) `

B

`30^(@) `

C

`60^(@)`

D

`90^(@)`

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The correct Answer is:
To solve the problem of finding the apparent dip when a dip circle is at right angles to the magnetic meridian, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - A dip circle is a device used to measure the angle of dip (or inclination) of the Earth's magnetic field. - The magnetic meridian is the plane that contains the magnetic field lines and the vertical component of the magnetic field. 2. **Identify Components of the Magnetic Field**: - The Earth's magnetic field can be resolved into two components: - **Vertical Component (BV)**: This is the component of the magnetic field acting vertically downwards. - **Horizontal Component (BH)**: This is the component of the magnetic field acting horizontally. 3. **Position of the Dip Circle**: - When the dip circle is at right angles to the magnetic meridian, it means the angle (α) between the dip circle's plane and the magnetic meridian is 90 degrees. 4. **Calculating the Horizontal Component in the Dip Circle's Plane**: - The horizontal component of the magnetic field in the plane of the dip circle (BH') can be expressed as: \[ BH' = BH \cdot \cos(\alpha) \] - Since α = 90 degrees, we have: \[ BH' = BH \cdot \cos(90^\circ) = BH \cdot 0 = 0 \] 5. **Resultant Magnetic Field in the Dip Circle's Plane**: - The vertical component remains the same (BV = VV). - Therefore, the resultant magnetic field (B) in the plane of the dip circle is purely vertical: \[ B = \sqrt{(BH')^2 + (BV)^2} = \sqrt{0^2 + VV^2} = VV \] 6. **Finding the Apparent Dip**: - The angle of dip (φ) in the dip circle's plane can be calculated using: \[ \tan(\phi) = \frac{BV}{BH'} \] - Since BH' = 0, this leads to: \[ \tan(\phi) = \frac{VV}{0} \] - This results in φ approaching infinity, which corresponds to: \[ \phi = \frac{\pi}{2} \text{ or } 90^\circ \] 7. **Conclusion**: - Thus, when the dip circle is at right angles to the magnetic meridian, the apparent dip is 90 degrees. ### Final Answer: The apparent dip when the dip circle is at right angles to the magnetic meridian is **90 degrees**. ---

To solve the problem of finding the apparent dip when a dip circle is at right angles to the magnetic meridian, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - A dip circle is a device used to measure the angle of dip (or inclination) of the Earth's magnetic field. - The magnetic meridian is the plane that contains the magnetic field lines and the vertical component of the magnetic field. ...
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The value of dip at a place is 45^@ . The plane of the dip circle is turned through 60^@ from the magnetic meridian. Find the apparent value of dip.

The true value of dip at a place is 30^(@) . The vertical plane carrying the needle is turned through 45^(@) from the magnetic meridian . Calculate the apparent value of dip .

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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-MAGNETISM-I-Exercise 2
  1. The angle between the earth's magnetic axis and the earth's geographic...

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  2. If a magnet is hanged with its magnetic axis then it stops in

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  3. A dip needle in a plane perpendicular to magnetic meridian will remain

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  4. A dip circle is at right angles to the magnetic meridian. What will be...

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  5. A magnetic needle suspended horizontally by an unspun silk fibre, osci...

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  6. Two lines of force due to a bar magnet

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  7. If a magnet of pole strenth m is divided into four parts such that the...

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  8. Torques tau(1) and tau(2) are required for a magnetic needle to remain...

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  9. A dip circle is taken to geomagnetic equator. The needle is allowed to...

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  10. At the magnetic north pole of the earth, the value of horizontal compo...

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  11. Magnetic dip was measured at various places on earth in one of the fol...

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  12. A magnet of magnetic moment M amd pole strenth m is divided in two equ...

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  13. A bar magnet when placed at an angle of 30^(@) to the direction of mag...

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  14. A toroid of n turns, mean radius R and cross-sectional radius a carrie...

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  15. The earth's magnetic field at a certain place has a horizontal compone...

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  16. A bar magnet of legth 3cm has point A and B along its axis at distance...

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  17. Two short magnets of equal dipole moment M are fastened perpendicularl...

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  18. The plane of dip circle is set in the geographic meridian and the appa...

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  19. Two short magnets of magnetic moment 1000 A-m^(2) are placed as shown...

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  20. Two identical short bar magnets, each having magnetic moment M, are pl...

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