The radius of the earth is `6.37xx10^(6)` m its mass `5.98xx10^(24)` kg determine the gravitational potential on the surface of the earth
Given `G=6.67 xx10^(-11) N-m^(2)//khg^(2)`

Options

A. `6.2616 xx10^(7) jkg^(-1)`
B. `-62.616xx10^(-7) jkg^(-1)`
C. `-6.2616xx10^(7) jkg^(-1)`
D. `62.619xx10^(7) j kg^(-1)`

Explanation

To determine the gravitational potential on the surface of the Earth, we can use the formula for gravitational potential \( V \):

\[ V = -\frac{G \cdot M}{R} \]

where:
- \( V \) is the gravitational potential,
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