The time period of the moon is T= 27.3 days and radius of orbit is `R_(m)=3.84xx10^(8)m` The value of centripetal acceleartion due to earht 's gravity is

Options

A. much smaller than the value of acceleration due to gravity g on the surface of the earth
B. is eual to the value of acceleration due to gravity g on the surface of the earth
C. much larger than the value of acceeration due to gravity g on the surface of the earth
D. either a or b

Answer

A

Explanation

`a=(4pi^(2)R_(m))/(T^(2))=4xx(22/7)^(2)xx(3.84xx10^(8))/(27.3xx24xx60xx60^(2)=0.0027 ms^(-2)`
Hence centripetal acceleration of the moon due to earth 's gravity is much smaller than the value of accelration due to gravity g on the surface of the earth