The pitentil energy of a satellite is given as
`PE= lambda(KE)`
where PE = potential energy of the satellite
KE = kinetic energy of the satellite
The vlaue of constant `lambda` is

Options

A. `-2`
B. 2
C. `-1//2`
D. `+1//2`

Answer

A

Explanation

PE of satellite `=(GmM_(E))/(R_(E)+h)`
`KE of satellite =1/2 (GmM_(E))/(R_(E)+h)`
KE of satellite `=1/2 (GmM_(E))/(R_(E)+h)`
`PE=-2 KE rarr lambda =-2`