The escape velocity of a body from the earth is `V_(e)` if the radius of earth contracts to `1//4` th of its value keeping the mass of the earth constant the escape velocity will be

Options

A. doubled
B. halved
C. tripled
D. unaltered

Answer

A

Explanation

Escape velocity `V_(e)=sqrt(2GM)/(R ),R=(R )/(4)`
opr `V_(e )=2 sqrt(2GM)/(R )`
since G and M are constant hence `V_(e )=2v_(e )`