A satellite is revolving round the earth with orbital speed `v_(0)` if it is imagined to stop suddenly the speed with which it will strike the surface of the earth would be `(v_(e)` - escape speed of a body from earth s surface)

Options

A. `(V_(e )^())/(v_(0))`
B. `2V_(0)`
C. `sqrt(v_(e )^(2)-v_(0)^(2))`
D. `sqrt(v_(e )^(2)-2v_(0)^(2))`

Answer

D

Explanation

`U_(2)=2(1/2 mv^(2)) rarr v_(0)v^(2)=(t)/(2)`
Now `1/2 mv^(2)=-u_(2)+u_(1)=u_(1)-u_(2)`
`=(mv_(e )^(2))/(2)-mv_(0)^(2)`
`therefore v=sqrt(v_(e )^(2)-2v_(0)^(2))`