In a satellite if the time of revolution is `T`, then kinetic energy is proportional to

Options

A. `(1)/(T)`
B. `(1)/(T^(2))`
C. `(1)/(T^(3))`
D. `T^(-2//3)`

Answer

D

Explanation

velocity of satellite `v=sqrt(GM)/(r )`
`therefore KE prop v^(2) prop (1)/(r )` and `T^(2) prop r^(3)`
`rarr KE prop T^(-2//3)`