A particle of mass 1 kg is moving in SHM with an amplitude 0.02 m and a frequency of 60 Hz. The maximum force (in N) acting on the particle is

Options

A. 188 `pi^(2)`
B. 144 `pi^(2)`
C. 288 `pi^(2)`
D. None of the above

Answer

C

Explanation

Maximum force = `m omega^(2)a = m 4 pi v^(2)a`
`= 1 xx 4 pi^(2) xx (60)^(2) xx 0.02 = 288 pi^(2)N`