An iron ball of mass M is hanged from the ceilling by a spring with a spring constant k. It executes a SHM with a period P. If the mass of the ball is increased by four times, the new period will be

Options

A. 4P
B. `(P)/(4)`
C. 2P
D. P

Answer

C

Explanation

The time period of the iron ball would be given by,
`P = 2pi sqrt((M)/(K))`
So, if mass of the ball is increased to 4 times of its initial mass, then the new period becomes
`P' = 2pi sqrt((4M)/(K)) = 2P`