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A particle executing simple harmonic mot...

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm / s . The frequency of its oscillation is

A

3 Hz

B

2 Hz

C

4 Hz

D

1 Hz

Text Solution

Verified by Experts

The correct Answer is:
D
Given, A = 5 cm
and `V_(max) = 314 cms^(-1)`
`rArr" "A omega = 31.4 rArr omega = (31.4)/(5)`
`rArr" "2 pi v = (31.4)/(5) rArr v = (31.4)/(2 xx 31.4 xx 5) = 1 Hz`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-OSCILLATIONS-EXERCISE 1
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