For a linear harmonic oscillator, its potential energy, kinetic energy and total energy given by `E_(P), K_(K) and E_(T)` respectively. Its maximum acceleration is given by

Options

A. `sqrt((2E_(P))/(m))`
B. `sqrt((2E_(K))/(m))`
C. `sqrt((2E_T)/(mA))`
D. `(2E_T)/(mA)`

Answer

D

Explanation

In a SHM. Maximum acceleration = `omega^(2)` A and Total energy
`E = (1)/(2)m omega^(2)A^(2)=(1)/(2)m A(omega^(2)A)`
`therefore" "omega^(2)A = (2E)/(mA)`= Maximum acceleration