When the potential energy of a particle executing simple harmonic motion is one-fourth of its maximum value during the oscillation, the displacement of the particle from the equilibrium position in terms of its amplitude a is

Options

A. `a//4`
B. `a//3`
C. `a//2`
D. `2a//3`

Answer

C

Explanation

Potential energy `= (1)/(2) m omega^(2)y^(2)=(1)/(4) xx (1)/(2) m omega^(2)a^(2)`
`y^(2)=(a^(2))/(4)rArr y = +- (a)/(2)`