If the length of second's pendulum is decreased by 2%, how many seconds it will lose per day

Options

A. 3927 s
B. 3427 s
C. 3737 s
D. 864 s

Answer

D

Explanation

According to question,
`T'=T sqrt((l+2l//100)/(l))`
`= T(1+(2)/(100))^(1//2)=2(1+(1)/(100))`
`therefore" "T'-T=(2)/(100)=(1)/(50)s`
Therefore, loss in second per day
`=(1//50)/(2)xx 24 xx 60 xx 60 = 864 s`