Home
Class 12
PHYSICS
A particle of mass 200 g executes a simp...

A particle of mass 200 g executes a simpel harmonit motion. The resrtoring force is provided by a spring of spring constant `80 N m^-1`. Find the time period.

A

0.315 s

B

0.15 s

C

0.05 s

D

0.02 s

Text Solution

Verified by Experts

The correct Answer is:
A
`T = 2pi sqrt((m)/(k)) = 2pi sqrt((0.2)/(80))= 0.315s`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise EXERCISE 2|49 Videos

  • OSCILLATIONS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET CORNER|29 Videos

  • OSCILLATIONS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET CORNER|29 Videos

  • MOCK TEST 5

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MCQs|42 Videos

  • PRACTICE SET 01

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PAPER 1 (PHYSICS & CHEMISTRY)|50 Videos

Similar Questions

Explore conceptually related problems

A paricle of mass 200 g executes a simple harmonic motion. The restorting force is provided by a spring of spring constant 80 N//m . Find the time period.

A particle executes simple harmonic motion under the restoring force provided by a spring. The time period is T. If the spring is divided in two equal parts and one part isused to continue the simple harmonic motion, the time period will

A block of mass 5 kg executes simple harmonic motion under the restoring force of a spring. The amplitude and the time period of the motion are 0.1 m and 3.14 s respectively. Fnd the maximum force exerted by the spring on the block.

A particle at the end of a spring executes simple harmonic motion with a period t_1 , while the corresponding period of another spring is t_2 . If the period of oscillation with the two springs in series is T. Then

A block of mass 2kg executes simple harmonic motion under the reading from at a spring .The angular and the time period of motion are 0.2 cm and 2pi sec respectively Find the maximum force execute by the spring in the block.

A mass M is suspended from a spring of negligible mass. The spring is pulled a little then released, so that the mass executes simple harmonic motion of time period T . If the mass is increased by m , the time period becomes (5T)/(3) . Find the ratio of m//M .

A particle at the end of a spring executes simple harmonic motion with a period t_(1) while the corresponding period for another spring is t_(2) if the oscillation with the two springs in series is T then

A particle of mass m= 5g is executing simple harmonic motion with an amplitude 0.3 m and time period pi//5 second. The maximum value of force acting on the particle is

A particle of mass m is attached to three identical springs of spring constant k as shwon in figure. The time period of vertical oscillation of the particle is

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-OSCILLATIONS-EXERCISE 1
  1. If the length of second's pendulum is decreased by 2%, how many second...

    Text Solution

    |

  2. Two simple pendulum of length 5m and 20m respectively are given small ...

    Text Solution

    |

  3. A and B are fixed points and the mass M is tied by strings at A and B....

    Text Solution

    |

  4. Two simple pendulum first of bob mass M(1) and length L(1) second of b...

    Text Solution

    |

  5. The mass and diameter of a planet are twice those of earth. What will ...

    Text Solution

    |

  6. A clock pendulum made of invar has a period of 0.5sec at 20^(@)C. If t...

    Text Solution

    |

  7. The time period of a simple pendulum in a stationary train is T. The t...

    Text Solution

    |

  8. In case of a simple pendulum, time period versus length is depicted by

    Text Solution

    |

  9. A simple spring has length l and force constant K. It is cut into two ...

    Text Solution

    |

  10. A particle of mass 200 g executes a simpel harmonit motion. The resrto...

    Text Solution

    |

  11. A massless spring, having force constant k, oscillates with frequency ...

    Text Solution

    |

  12. An object suspended from a spring exhibits oscillations of period T. N...

    Text Solution

    |

  13. If k(s) and k(p), respectively are effective spring constants in serie...

    Text Solution

    |

  14. If f is the frequency when mass m is attached to a spring of spring co...

    Text Solution

    |

  15. Frequency of oscillation is proportional to

    Text Solution

    |

  16. In the figure, S(1) and S(2) are identical springs. The oscillation fr...

    Text Solution

    |

  17. A clock S is based on oscillations of a spring and clock P is based on...

    Text Solution

    |

  18. In case of a forced vibration, the resonance wave becomes very sharp w...

    Text Solution

    |

  19. The amplitude of damped oscillator becomes 1/3 in 2s. Its amplitude af...

    Text Solution

    |

  20. If the differential equation given by (d^(2)y)/(dt^(2))+2k(dy)/(dt)+om...

    Text Solution

    |